Why do I need systems of equations to mix solutions?

When you mix two strengths of something, two facts must hold at once: the amounts add up to the total, and the active ingredient adds up to the target strength. That's a system of two equations. Solving it tells you exactly how much of each to pour, whether it's fertilizer, cleaner, paint, or medicine.

A10% strength10 L+B40% strength10 L=Mix25% strength20 L at 25%
Use this much A
10 L
Use this much B
10 L

Challenge: Find a mix that uses equal amounts of A and B. Done!

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Play

Pick two strengths and the one you want. The beakers show how much of each to pour.

Challenge: Find a mix that uses equal amounts of A and B. The box under the picture turns green when you get it.

Stuck? Pick one of the examples from the “Try an example” menu, or press “New example.”

Understand

{x+y=Vax+by=cV\begin{cases} x + y = V \\ a x + b y = c V \end{cases}

Two unknowns, xx and yy, need two equations:

x+y=Vax+by=cVx + y = V \qquad a x + b y = c V

The first says the amounts add up. The second says the active ingredient adds up. Substitute y=V−xy = V - x into the second and solve:

x=V c−ba−bx = V\,\frac{c - b}{a - b}

If a=ba = b, the denominator is zero, which is the math saying that two equal strengths can't make a different one.

Use

Every input has a unit menu, so you can type values in the units you already have. Results follow your units.

Show the work

  1. Total amountx + y = 20
  2. Amount of the active ingredient0.1x + 0.4y = 0.25 \times 20
  3. Solve for xx = V\frac{c - b}{a - b} = 20 \times \frac{25 - 40}{10 - 40} = 10
  4. Then yy = 20 - 10 = 10

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Enter strengths as percentages and the total you need. For dilution with plain water, set one strength to 0%.

  • Add the stronger part to the weaker part, especially with acids.
  • Measure by volume unless the label gives percent by weight.

For learning and estimation. Verify with applicable codes, standards, and a qualified professional before using in design, construction, or safety-critical work.

Cheat card

x+y=Vx + y = V
ax+by=cVa x + b y = c V
x=V c−ba−bx = V\,\frac{c - b}{a - b}
SymbolMeaningUnit
x,yx, yamounts of A and BL
a,ba, bstrengths of A and B%
cctarget strength%
VVtotal amountL
  • The target must lie between the two strengths. You can't mix two weak solutions into a strong one.
  • Water counts as a 0% solution when diluting.
  • Check by computing the active ingredient in the final mix.

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Where it’s used

  • Chemistry
    Chemists and nurses dilute stock solutions to exact concentrations.
  • Home Projects
    Mixing cleaning concentrate or paint tints to a target strength.
  • Gardening
    Blending two fertilizers to get the nitrogen percentage a lawn needs.

Questions people ask

How do I dilute a solution to a lower strength?

Use water as the second solution (0%). To make 4 L of 10% from 60% bleach, use about 0.67 L of bleach and 3.33 L of water.

Why can't I reach any strength I want?

A mix is always between its ingredients. From 10% and 40% you can make anything from 10% to 40%, but not 60%.

What happens if both solutions are the same strength?

Every mix has that same strength, so the system has no solution for any other target. The site shows