Why do I need Ohm's law to check voltage drop in a wire?

Wire has resistance, so current flowing through it loses some voltage before it reaches the load. Ohm's law gives that loss: current times the wire's resistance. Too much drop dims lights, slows motors, and wastes power as heat. Electricians usually keep the drop under about 3 percent of the supply.

supply120 Vat load119 V reaches the load3% guidelinelost in the wire: 1 V (0.83%) · 5 W of heatWithin the common 3% guideline for branch circuits.5 A through 0.2 Ω of wire
Voltage drop
1 V
Drop (% of supply)
0.833%
Power lost as heat
5 W
Voltage at the load
119 V

Challenge: Keep the drop within 3%. Done!

Play

Raise the current or the wire resistance. Watch the hatched part of the bar — voltage lost in the wire — grow.

Challenge: Keep the drop within 3%. The box under the picture turns green when you get it.

Stuck? Pick one of the examples from the “Try an example” menu, or press “New example.”

Understand

ΔV=IR\Delta V = I R

The wire is just another resistor in the circuit, in series with the load. Ohm's law applies to it too:

ΔV=IR\Delta V = I R

The top bar is the supply. The bottom bar is what reaches the load. The hatched part is lost in the wire. The dashed line marks the common 3% guideline.

Heat in the wire grows with the square of the current, P=I2RP = I^2R, so a heavy load on thin wire gets expensive and warm fast.

Use

Every input has a unit menu, so you can type values in the units you already have. Results follow your units.

Show the work

  1. Ohm’s law on the wire\Delta V = IR = 5 \times 0.2 = 1\,\mathrm{V}
  2. As a percent of supply\frac{1}{120} \times 100 = 0.8333\%
  3. Heat in the wireP = I^2R = (5)^2 \times 0.2 = 5\,\mathrm{W}

Export

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Enter the current (or link it from the appliance-current exhibit) and the wire resistance (or link it from the wire-resistance exhibit).

  • Use the resistance of both conductors, out and back.
  • Motors want less drop than heaters. Some equipment needs 2% or less.

For learning and estimation. Verify with applicable codes, standards, and a qualified professional before using in design, construction, or safety-critical work.

Cheat card

ΔV=IR\Delta V = IR
%drop=ΔVV×100\%\text{drop} = \frac{\Delta V}{V} \times 100
Ploss=I2RP_{\text{loss}} = I^2 R
SymbolMeaningUnit
ΔV\Delta Vvoltage lost in the wireV
IIcurrentA
RRresistance of both conductorsΩ
VVsupply voltageV
  • Low-voltage systems (12 V) feel voltage drop far more than 120 V circuits.
  • Heat loss grows with the square of current. Double the current, four times the heat.
  • Fixes are thicker wire, shorter runs, or a higher supply voltage.

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Where it’s used

  • Electrical & Electronics
    Electricians check voltage drop on long branch circuits and feeders, often to a 3% or 5% limit.
  • Trades
    Solar and RV installers size battery cables so 12 V systems don't lose half their voltage.
  • Home Projects
    It's why a tool on a long, thin extension cord runs weak and the cord gets warm.

Questions people ask

How do I calculate voltage drop?

Multiply the current by the resistance of both wires. 12.5 A through 0.16 Ω drops 2 V.

How much voltage drop is acceptable?

A common guideline is 3% for a branch circuit and 5% total from the service to the load. Check your local code.

Where does the lost voltage go?

It becomes heat in the wire, I²R watts of it. That's why undersized wire runs warm.