How far will my car's suspension sag when I load it?

Hooke's law says a spring compresses in proportion to the force: x = F ÷ k. Split the load between the springs carrying it, then divide by the spring rate. Five hundred pounds on two 150 lb/in rear springs sags each about 1.7 inches. Twice the load gives twice the sag, until the bump stops.

bump stopF = 220x (slope = spring rate)1.36 instop300 lbf each
Sag
1.36 in
Travel used
45.5%
Travel left for bumps
1.64 in

Challenge: Carry 1,000 lb or more while using no more than half the travel. Done!

Cargo, passengers, or a trailer’s tongue weight.
Pounds of force per inch of compression, measured at the wheel. About 100 to 200 for cars, 300 to 600 for pickup leaf springs.
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Play

Load the overloaded compact car, then find the spring rate that keeps it off the stops.

Challenge: Carry 1,000 lb or more while using no more than half the travel. The box under the picture turns green when you get it.

Stuck? Pick one of the examples from the “Try an example” menu, or press “New example.”

Understand

x=Fkx = \frac{F}{k}

A spring pushes back in proportion to how far you squeeze it. That's Hooke's law:

F=kxF = kx

The spring rate kk is the slope of the line. Split the load between the springs that carry it, then divide by kk to get the sag.

The dashed line is the bump stop. Past it, the spring has nothing left for potholes.

Use

Every input has a unit menu, so you can type values in the units you already have. Results follow your units.

Show the work

  1. Share the load between the springsF = \frac{1200}{4} = 300\ \text{lbf}
  2. Hooke’s law: force = rate × compressionF = kx
  3. Solve for the compressionx = \frac{F}{k} = \frac{300}{220} = 1.364\ \text{in}
  4. Share of the travel used\frac{1.364}{3} = 45.45\%

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Set the load, how many springs share it, and the spring rate. "More settings" changes the travel left before the bump stops.

  • Spring rates here are measured at the wheel. Rates on the spring itself are usually higher, because the spring sits closer to the pivot.
  • Real loads rarely split evenly. A trunk load sits mostly on the rear axle.

For learning and estimation. Verify with applicable codes, standards, and a qualified professional before using in design, construction, or safety-critical work.

Cheat card

F=kxF = kx
x=Fkx = \frac{F}{k}
Feach=WnF_{\text{each}} = \frac{W}{n}
SymbolMeaningUnit
FFforce on one springlbf
kkspring ratelb/in
xxcompression (sag)in
nnnumber of springs sharing the load
  • The graph is a straight line through zero. Its slope is the spring rate.
  • Springs share the load. Four springs each carry a quarter.
  • A stiffer spring sags less but rides harsher over bumps.

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Where it’s used

  • Mechanical
    Suspension engineers pick spring rates so a loaded car keeps enough travel for bumps.
  • Physics
    Hooke's law is the first model of any spring, from bathroom scales to atomic bonds.
  • Driving & Travel
    Check how much a trailer or a loaded trunk will squat the back of the car.

Questions people ask

What is Hooke's law?

The force on a spring equals its rate times how far it compresses or stretches, F = kx. It holds until the spring runs out of travel or is bent past its limit.

What is a spring rate?

How much force it takes to compress the spring by one unit, such as 150 lb per inch. Higher is stiffer.

Why does the back of my car squat when towing?

The tongue weight sits behind the rear axle and pushes those springs down. It also lifts the front a little, so the rear often carries a bit more than the tongue weight itself.