When should I start my descent, and how fast should I descend?

On a 3 degree path you lose about 318 feet per nautical mile, the tangent of 3 degrees times 6,076 feet. Divide the altitude to lose by that to get the distance to start down. Multiply groundspeed in nautical miles per minute by 318 for the descent rate, about five times groundspeed.

start down 17.5 nm out7,500 ft1,000 ft743 ft/min at 120 kt3.5° path: 372 ft per nm, 8.75 min to lose 6,500 ftvertical scale stretched
Start down this far out
17.5 nm
Descent rate
743 ft/min
Time to descend
8.75 min

E6B: Training aid only, not for navigation or flight. Verify with your POH/AFM and approved sources.

3° is standard for approaches and comfortable for passengers.

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Speed up the airplane and watch the descent rate climb while the distance stays put.

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Understand

d=Δh6076 tan⁡θd = \frac{\Delta h}{6076\,\tan\theta}

A descent at a fixed angle θ\theta is a right triangle. The tangent links the altitude lost to the ground covered:

tan⁡θ=height lostdistance\tan\theta = \frac{\text{height lost}}{\text{distance}}

One nautical mile is 6,076 ft, so a 3° path loses 6076tan⁡3∘≈3186076\tan 3^\circ \approx 318 ft per nm. Divide the altitude to lose by that to find where to start. Multiply by nautical miles per minute to get feet per minute.

The picture stretches the height so you can see the path. A real 3° slope is almost flat.

Use

Every input has a unit menu, so you can type values in the units you already have. Results follow your units.

Show the work

  1. Feet lost per nautical mile6076 \tan 3.5^\circ = 371.6\ \text{ft/nm}
  2. Distance to start downd = \frac{7500 - 1000}{6076\tan 3.5^\circ} = 17.49\ \text{nm}
  3. Descent rate = groundspeed × feet per nm\frac{120}{60} \times 371.6 = 743.3\ \text{ft/min}
  4. Rules of thumb for 3°\text{nm} \approx 3 \times \frac{\Delta h}{1000} = 19.5,\quad \text{ft/min} \approx 5 \times \text{GS} = 600

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Enter cruise and target altitudes, the groundspeed you expect in the descent, and the path angle.

  • Groundspeed in the descent is often higher than cruise. Use what you expect, including wind.
  • Instrument approaches publish their own descent angles and altitudes. Always fly those.

For learning and estimation. Verify with applicable codes, standards, and a qualified professional before using in design, construction, or safety-critical work.

Cheat card

d=Δh6076tan⁡θd = \frac{\Delta h}{6076\tan\theta}
fpm=GS60×6076tan⁡θ\text{fpm} = \frac{\text{GS}}{60} \times 6076\tan\theta
3∘: d≈3×Δh1000,  fpm≈5×GS3^\circ:\ d \approx 3 \times \frac{\Delta h}{1000},\ \ \text{fpm} \approx 5 \times \text{GS}
SymbolMeaningUnit
Δh\Delta haltitude to loseft
θ\thetadescent path angle°
GS\text{GS}groundspeedkt
  • The distance depends only on the angle and the altitude. Speed changes the rate, not where to start.
  • Start a little early. It's easier to level off than to dive to catch up.
  • Follow published approach procedures and ATC instructions. They set the real descent points.

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Where it’s used

  • Aerospace
    Pilots and flight management computers plan top of descent so the airplane arrives at pattern or approach altitude without a steep dive.
  • Driving & Travel
    It's why airliners start down 100 miles or more from the airport.

Questions people ask

How do you calculate top of descent?

For a 3° path, multiply the thousands of feet to lose by 3 to get nautical miles. Losing 4,000 ft needs about 12 nm. The exact answer divides the altitude by 6,076 tan 3° = 318 ft per nm.

What descent rate gives a 3-degree path?

About five times your groundspeed in feet per minute. At 120 kt, that's roughly 600 ft/min. The exact value is 637 ft/min.

Why does the descent rate depend on groundspeed?

The angle fixes feet lost per nautical mile. Covering nautical miles faster means losing those feet faster, so the rate in feet per minute goes up.