What is the rule of thumb for density altitude?

Start with pressure altitude: field elevation plus (29.92 minus the altimeter setting) times 1,000. Find the standard temperature there, 15 °C minus 2 °C per 1,000 feet. Then add 120 feet for every degree Celsius the air is warmer than standard, or subtract it when colder.

altitude (ft)field 4,000 ftpressure altitude 4,120 ftdensity altitude ≈ 5,949 ft22 °C vs. standard 6.76 °C+15.2 °C × 120 ft = +1,829 ft
Density altitude (rule of thumb)
5950 ft
Pressure altitude
4120 ft
Standard temperature there
6.76 °C

E6B: Training aid only, not for navigation or flight. Verify with your POH/AFM and approved sources.

From ATIS or the METAR, like 30.12 (or switch to hPa).

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Warm the day up one degree at a time and count 120 feet each step.

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Understand

DA≈PA+120 (OAT−TISA)\text{DA} \approx \text{PA} + 120\,(\text{OAT} - T_{\text{ISA}})

Density altitude is a straight-line linear correction, twice:

  1. Pressure: each inch of mercury below 29.92 adds 1,000 ft.
  2. Temperature: each degree Celsius above standard adds 120 ft.

DA≈PA+120 (OAT−TISA)\text{DA} \approx \text{PA} + 120\,(\text{OAT} - T_{\text{ISA}})

The real atmosphere isn't linear. Density falls with a power of altitude. But over the few thousand feet that matter for takeoff, a straight line fits well enough to do in your head.

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Every input has a unit menu, so you can type values in the units you already have. Results follow your units.

Show the work

  1. Pressure altitude: 1,000 ft per inch of mercury\text{PA} = 4000 + (29.92 - 29.8) \times 1000 = 4120\ \text{ft}
  2. Standard temperature: 15 °C, minus 2 °C per 1,000 ftT_{\text{ISA}} = 15 - 2 \times \frac{4120}{1000} = 6.76\ ^\circ\mathrm{C}
  3. Add 120 ft per °C above standard\text{DA} \approx 4120 + 120 \times (22 - 6.76) = 5949\ \text{ft}

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Enter field elevation, the altimeter setting, and the temperature. For the exact answer, including humidity, open the exact density altitude tool linked above.

  • Use POH performance charts with pressure altitude and temperature for real takeoff and climb numbers.

For learning and estimation. Verify with applicable codes, standards, and a qualified professional before using in design, construction, or safety-critical work.

Cheat card

PA=elev+(29.92−altimeter)×1000\text{PA} = \text{elev} + (29.92 - \text{altimeter}) \times 1000
TISA=15−2 PA1000 ∘CT_{\text{ISA}} = 15 - 2\,\frac{\text{PA}}{1000}\ ^\circ\mathrm{C}
DA≈PA+120 (OAT−TISA)\text{DA} \approx \text{PA} + 120\,(\text{OAT} - T_{\text{ISA}})
SymbolMeaningUnit
PA\text{PA}pressure altitudeft
OAT\text{OAT}outside air temperature°C
TISAT_{\text{ISA}}standard temperature at that altitude°C
  • Each 0.01 inHg below 29.92 adds about 10 ft of pressure altitude.
  • The rule runs a little high on hot days compared with the exact formula, which errs on the safe side.
  • Humidity isn't in the rule. On humid days, the exact tool with dew point gives a higher answer.

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Where it’s used

  • Aerospace
    Pilots use the 120-feet-per-degree rule for a quick density altitude check before takeoff.
  • Driving & Travel
    It explains why summer afternoons at mountain airports feel like flying thousands of feet higher.

Questions people ask

What is the density altitude rule of thumb?

Density altitude ≈ pressure altitude + 120 × (OAT − standard temperature). Standard temperature is 15 °C at sea level, dropping 2 °C per 1,000 ft.

How accurate is the rule of thumb?

Within a few hundred feet for typical conditions. On a 30 °C day in Denver it gives about 8,290 ft, versus about 8,080 ft from the exact dry-air formula. That's a slightly conservative result.

Where does 120 feet per degree come from?

Near the ground, a 1 °C rise in temperature thins the air about as much as climbing roughly 120 ft in the standard atmosphere. It's a straight-line fit to the exact curve.